In methyl alcohol solution,bromine reacts with ethylene (ethene) to yield $BrCH_2CH_2OCH_3$ in addition to $1, 2-dibromoethane$ because

  • A
    the methyl alcohol solvates the bromine
  • B
    the ion formed initially may react with $Br^{-}$ or $CH_3OH$
  • C
    this is a free radical reaction
  • D
    the reaction follows Markovnikov's rule

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